Question 10: Find the natural numbers n such that the fraction \(\frac{{n + 3}}{n}\) has an integer value

A. {1; 3}

B. {-1; -3}

C. {-3; 3}

D. {-3; -first; first; 3}

We have: \(\frac{{n + 3}}{n} = \frac{n}{n} + \frac{3}{n} = 1 + \frac{3}{n}\)

To \(\frac{{n + 3}}{n}\) is an integer then \(\frac{{ 3}}{n}\) is an integer

\(\begin{array}{l} = > n \in U(3) = {\rm{\{ }} \pm 1; \pm 3\} \\ = > n \in {\rm{\{ }} – 3; – 1;1;3\} \end{array}\)

Choose the EASY answer

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