Question 26: $\text { Find } x \text { in an integer such that the expression } A=\frac{x-13}{x+3} \text { reaches the minimum value. }$

A. x=-1

B. x=4

C. x=2

D. x=-2

$\mathrm{A}=\frac{x-13}{x+3}=\frac{(x+3)-16}{x+3}=1-\frac{16}{x+3} $

It’s easy for A min $\frac{16}{x+3}{ }_{\max } \Rightarrow(x+3) \min \Leftrightarrow \mathrm{x}_{\text {min }}$

If x+3<0$\, the smallest value of A cannot be found
If $x+3>0 \Leftrightarrow x>-3$ where x is integer $(x+3) _\min$ when x=-2

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Question 26: \(\text { Find } x \text { in an integer such that the expression } A=\frac{x-13}{x+3} \text { reaches the minimum value. }\)