Question 48: Which fraction is equal to the fraction \({301\over 403}\) whose numerator and denominator are both positive and three-digit fraction?

We have:

\(\begin{array}{l} \frac{{301}}{{403}} = \frac{{301.2}}{{403.2}} = \frac{{602}}{{806}}(TM) )\\ \frac{{301}}{{403}} = \frac{{301.3}}{{403.3}} = \frac{{903}}{{1209}}(L) \end{array}\ )

Therefore, in the case of multiplying both numerator and denominator by a natural number greater than 33, we can also eliminate them.

Also fractions \({301\over 403}\) so it cannot be shortened.

So the required fraction is \({602\over 806}\)