Question 8: Let the set A = {0; first; 2; 3} . Set B consists of fractions whose numerator and denominator are in A, where the numerator is different from the denominator. The number of elements of set B is:

Set B includes the parts of numbers whose numerator and denominator are in A, where the numerator is different from the denominator

\(= > B = \left\{ {\frac{0}{1};\frac{0}{2};\frac{0}{3};\frac{1}{2};\frac{ 1}{3};\frac{2}{3};\frac{2}{1};\frac{3}{1};\frac{3}{2}} \right\}\)

So set B has 9 elements

Choose the EASY answer