Question 29: The function (y = frac{1}{3}{x^3} + 2{x^2} + 3x – 1) has the extreme points of

Question 29: The function \(y = \frac{1}{3}{x^3} + 2{x^2} + 3x – 1\) has the extreme points of

A. \(\left[\begin{array}{l}x=1\\x=3\end{array}\right\)[\begin{array}{l}x=1\x=3\end{array}\right\)

B. \(\left[\begin{array}{l}x=–1\\x=3\end{array}\right\)[\begin{array}{l}x=–1\x=3\end{array}\right\)

C. \(\left[\begin{array}{l}x=–1\\x=–3\end{array}\right\)[\begin{array}{l}x=–1\x=–3\end{array}\right\)

D. \(Function has no extrema.\)

We have

\(y’ = {x^2} + 4x + 3 = 0 \Leftrightarrow \left[\begin{array}{l}x=–1\\x=–3\end{array}\right\)[\begin{array}{l}x=–1\x=–3\end{array}\right\)

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