Question 38: The function \(y=x^3-3x^2\) is inverse on which of the following intervals
TXĐ:\(D=\mathbb{R}\)
Then \(y’=3x^2-6x\)
\(y’=0\Leftrightarrow3x^2-6x=0\)
\(\Leftrightarrow \left[\begin{array}{l}x=0\Rightarrowf(0)=0\\x=2\Rightarrowf(0)=-4\end{array}\right\)
The variation table of the function has the form
Relying on the table of variation of the above inverse function (0,2)
===============