Question 4: Find the minimum point of the function (y = frac{1}{3}{x^3} – 2{x^2} + 3x + 1)

Question 4: Find the minimum point of the function \(y = \frac{1}{3}{x^3} – 2{x^2} + 3x + 1\)

A. x = – 3

B. x = 1

C. x = 3

D. x = – 1

Deterministic Set \(D = \mathbb{R}\)

We have \(y’ = {x^2} – 4x + 3\)

\(y’ = 0 \Leftrightarrow x = 1 \vee x = 3\)

\(y” = 2x – 4\)

+) \(y”(1) = – 2 < 0\). The function reaches its maximum at the point x = 1.

+) \(y”(3) = 2 > 0\). The function reaches its minimum at the point x = 3.

===============

Reader Interactions