Question 49: Given two polynomial functions \(y = f\left( x \right), y = g\left( x \right)\) whose graphs are two curves in the figure. Knowing that the function graph \(y = f\left( x \right)\) has exactly one extreme point A, the function graph \(y = g\left( x \right)\) has exactly one extreme points are B and \(AB = \frac{7}{4}\). How many integer values of parameter m are in the interval \(\left( { – 5;5} \right)\) for the function \(y = \left| {\left| {f\left( x \right) ) – g\left( x \right)} \right| + m} \right|\) has exactly 5 extremes?
Put \(h\left( x \right) = f\left( x \right) – g\left( x \right)\), we have: \(h’\left( x \right) = f’\ left( x \right) – g’\left( x \right); h’\left( x \right) = 0 \Leftrightarrow x = {x_0}\);
\(h\left( x \right) = 0 \Leftrightarrow x = {x_1}\) or \(x = {x_2}\) (\({x_1} < {x_0} < {x_2}\));
\(h\left( {{x_0}} \right) = f\left( {{x_0}} \right) – g\left( {{x_0}} \right) = – \frac{7}{4} \).
The variation table of the function \(y = h\left( x \right)\) is:
The table of variation of the function \(y = k\left( x \right) = \left| {f\left( x \right) – g\left( x \right)} \right|\) is:
Therefore, the function \(y = k\left( x \right) + m\) also has three extremes.
Because the number of extreme points of the function \(y = \left| {k\left( x \right) + m} \right|\) is equal to the sum of the extreme points of the function \(y = k\left( x \) right) + m\) and the number of simple and odd multiples of the equation \(k\left( x \right) + m = 0\), whose function \(y = k\left( x \right) + m\) also has three extreme points, so the function \(y = \left| {\left| {f\left( x \right) – g\left( x \right)} \right| + m} \ right|\) has exactly five extremes when the equation \(k\left( x \right) + m = 0\) has exactly two simple roots (or odd multiples).
Based on the variation table of the function \(y = k\left( x \right)\), the equation \(k\left( x \right) + m = 0\) has exactly two simple roots (or odd multiples). ) if and only if \( – m \ge \frac{7}{4} \Leftrightarrow m \le – \frac{7}{4}\).
Since , \(m \le – \frac{7}{4}\) and \(m \in \left( { – 5;5} \right)\) \(m \in \left\{ { – 4; – 3; – 2} \right\}\)
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