Verse 36: . The function (y=f(x)=-x^3+3x^2-1) covariates on intervals:

TXĐ: \(D=\mathbb{R}\)

\(y’=-3x^2+6x\)

\(y’=0\Leftrightarrow-3x^2+6x=0\)

\(\Leftrightarrow \left[\begin{array}{l}x=0\\x=2\end{array}\right\)

Variation table

Looking at the table of variables, we see that the above covariate function (0, 2)