Question 33: Find x: \( {\mkern 1mu} x \vdots 18{\mkern 1mu} ;{\mkern 1mu} x \vdots 30{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \) and 0<x<100

We have: x⋮18;x⋮30⇒x∈BC(18,30)

We have:

\(\begin{array}{*{20}{l}} {18 = {{2.3}^2};{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} 30 = 2.3.5}\\ { \Rightarrow BCNN\left( {18;30} \right) = \left\{ {0;90;180;270;…} \right\}} \end {array}\)

Since 0

So x=90

Select REMOVE