Question 17: Total A=1+3+5+7+9+…+2017+2019 has the answer:

A=1+3+5+7+9+…+2017+2019

The distance between two consecutive numbers is: 3 – 1 = 2 units.

The term in the sum sequence is: (2019−1):2+1=1010 (term)

The sum of the series is: 2019+1)×1010:2=1020100.