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You are here: Home / Natural numbers / Question 32: Let x1​ be a satisfying natural number (x+74)−318=200 and x2​ be a satisfying natural number (x:23+45).67=8911. Then what is ({x_1} + 2{x_2})​ equal to?

Question 32: Let x1​ be a satisfying natural number (x+74)−318=200 and x2​ be a satisfying natural number (x:23+45).67=8911. Then what is ({x_1} + 2{x_2})​ equal to?

30/08/2021 //  by admin//  Leave a Comment

Question 32: Let x1​ be a satisfying natural number (x+74)−318=200 and x2​ be a satisfying natural number (x:23+45).67=8911. Then what is \({x_1} + 2{x_2}\)​ equal to?





– Total \({x_1} + 2{x_2}\)

+ We have: (x+74)−318=200

x + 74 = 200 + 318

x + 74 = 518

x = 518 – 74

x = 444

So xfirst​=444.

+ We have: (x:23+45).67=8911

x:23 + 45 = 8911:67

x:23 + 45 = 133

x:23 = 133 – 45

x:23 = 88

x = 88.23

x = 2024

So x2​=2024.

Then \({x_1} + 2{x_2} = 444 + 2.2024 = 4492\)

Select REMOVE

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Category: Natural numbersTag: Adding and Multiplying of natural numbers

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