Question 1: Performing the calculation \(\begin{aligned} (x-1)(x+2)(3 x-1) \end{aligned}\) we get:
\(\begin{aligned} (x-1)(x+2)(3 x-1) &=\left(x^{2}+2 xx-2\right)(3 x-1)=\left (x^{2}+x-2\right)(3 x-1) \\ &=3 x^{3}-x^{2}+3 x^{2}-x-6 x+2 \ \ &=3 x^{3}+2 x^{2}-7 x+2 \end{aligned}\)
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