Question 15: Factoring polynomials: \( {x^2} + 6x + 9 – {y^2}\)

A. \(\left( {x – y + 3} \right)\left( {x – y – 3} \right)\)

B. \(\left( {x – y – 3} \right)\left( {x + y + 3} \right)\)

C. \(\left( {x – y + 3} \right)\left( {x + y + 3} \right)\)

D. \(( {x – y + 3} )^3\)

We have:

\( {x^2} + 6x + 9 – {y^2} = {\left( {x + 3} \right)^2} – {y^2} = \left( {x – y + 3} \right)\left( {x + y + 3} \right)\)

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