Question 2: Multiply: \( \frac{1}{2}{x^2}y\left( {2{x^3} – \frac{2}{5}x{y^2} – 1 } \right)\)
We have:
\( {\mkern 1mu} \frac{1}{2}{x^2}y\left( {2{x^3} – \frac{2}{5}x{y^2} – 1} \ right) = \frac{1}{2}{x^2}y.2{x^3} – \frac{1}{2}{x^2}y\frac{2}{5}x{y ^2} – \frac{1}{2}{x^2}y = {x^5}y – \frac{1}{5}{x^3}{y^3} – \frac{1} {2}{x^2}y\)
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