Question 21: Factoring polynomials: \( 3{x^3} – 6{x^2} + 3x \)

04/01/2022 // by admin// Leave a Comment

Question 21: Factoring polynomials: \( 3{x^3} – 6{x^2} + 3x \)

A. \(x{\left( {x +1} \right)^2}\)

B. \( 3x{\left( {x +1} \right)^2}\)

C. \( 3x{\left( {x – 1} \right)^2}\)

D. \( x{\left( {x – 1} \right)^2}\)

We have:

\( 3{x^3} – 6{x^2} + 3x = 3x\left( {{x^2} – 2x + 1} \right) = 3x{\left( {x – 1} \right) ^2}\)

===============

« Question 20: Find x, y, z knowing \(\frac{x}{6} = \frac{y}{9} = \frac{z}{7};x + y + z = 11\)

Question 21: Ms. Hoa has some lotus flowers. If you bundle into bundles of 3 flowers, 5 flowers or 7 flowers, they will all fit. How many lotus flowers does Hoa have? Know that Hoa has about 200 to 300 flowers. »

Leave a Reply Cancel reply