Question 35: Performing division \(\left( {8{x^3} – 27{y^3}} \right):(2x – 3y) \) we get
\(\left( {8{x^3} – 27{y^3}} \right):(2x – 3y) = (2x – 3y)\left( {4{x^2} + 6xy + 9{ y^2}} \right):(2x – 3y) = 4{x^2} + 6xy + 9{y^2}\)
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Question 35: Performing division \(\left( {8{x^3} – 27{y^3}} \right):(2x – 3y) \) we get
\(\left( {8{x^3} – 27{y^3}} \right):(2x – 3y) = (2x – 3y)\left( {4{x^2} + 6xy + 9{ y^2}} \right):(2x – 3y) = 4{x^2} + 6xy + 9{y^2}\)
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