Question 48: The value of the expression \(\begin{array}{l} A = {\left( { – {x^3}y} \right)^5}:\left( { – {x^{12 }}{y^2}} \right) = {x^3}{y^3} \end{array}\) at x=2 and \(y = – \frac{1}{2}\)

\(\begin{array}{l} A = {\left( { – {x^3}y} \right)^5}:\left( { – {x^{12}}{y^2}} \right) = {x^3}{y^3} \end{array}\)

Replace x=2, \(y = – \frac{1}{2}\) I can enter A

\(A = {2^3}. {\left( {\frac{1}{2}} \right)^3} = 1\)