Question 7: Factoring polynomials: \( x^3 − x ^2 − 6 x \)

\( {x^3} – {x^2} – 6x = x\left( {{x^2} – x – 6} \right) = x\left( {{x^2} – 3x + 2x – 6} \right) = x\left[ {x\left( {x – 3} \right) + 2\left( {x – 3} \right)} \right] = x\left( {x – 3} \right)\left( {x + 2} \right).\)