Question 1: Let \( A = \sqrt {x + 2} + \frac{3}{{11}}\) Find the minimum value of A.

A. \(- \frac{3}{{11}}\)

B. \( \frac{3}{{11}}\)

C. \(- \frac{2}{{11}}\)

D. \( \frac{2}{{11}}\)

Because \( \sqrt {x + 2} \ge 0\) for every x should \( \sqrt {x + 2} + \frac{3}{{11}} \ge \frac{3}{{11}}\) for every x.

I guess \( A \ge \frac{3}{{11}}\)

So A has a minimum value of . \( \frac{3}{{11}}\) if and only if x+2=0 or x=−2

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