Question 16: Find x knowing \(\frac{{x + 1}}{{ – 6}} = \frac{2}{3}\)

\(\begin{aligned}&\frac{{x + 1}}{{ – 6}} = \frac{2}{3}\\ &3.\left( {x + 1} \right) = \left ( { – 6} \right).2\\ &3.\left( {x + 1} \right) = – 12\\ &x + 1 = \left( { – 12} \right):3\\ &x + 1 = – 4\\ &x = – 4 – 1\\ &x = – 5\end{aligned} \)