Question 2: Find the minimum value of the following expression: \(C = \sqrt {x + 5} – 3\)

Deterministic conditions \(x \ge – 5\)

Therefore \(\sqrt {x + 5} \ge = 0 \Rightarrow \sqrt {x + 5} – 3 \ge – 3 \Rightarrow – 5 – \sqrt {x + 3} \le – 5\)

The sign “=” occurs when x+5=0 deduces x=-5

So max B = – 3 when x = – 5