Question 21: The result of \(9 \cdot {\left( { – \frac{1}{3}} \right)^3} + \frac{1}{6} \cdot \sqrt 4\) is
\(9 \cdot {\left( { – \frac{1}{3}} \right)^3} + \frac{1}{6} \cdot \sqrt 4 = 9 \cdot \left( { – \ frac{1}{{27}}} \right) + \frac{1}{6} \cdot 2 = \frac{{ – 1}}{3} + \frac{1}{3} = 0\)
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