Question 23: Find x knowing \(\frac{{x + 1}}{7} = \frac{{11}}{3}\)

\(\begin{aligned}&\frac{{x + 1}}{7} = \frac{{11}}{3}\\ &3.\left( {x + 1} \right) = 11.7\\ &3.\left( {x + 1} \right) = 77\\ &x + 1 = \frac{{77}}{3}\\ &x = \frac{{77}}{3} – 1\\ &x = \frac{{74}}{3}\end{aligned} \)