Question 39: Find x knowing \( \frac{{x – 1,2}}{3} = \frac{4}{5}\)

\(\begin{aligned} &\frac{{x – 1,2}}{3} = \frac{4}{5}\\ &5\left( {x – 1,2} \right) = 3.4\ \&5\left( {x – 1,2} \right) = 12\\ &x – 1.2 = 12:5\\ &x – 1.2 = 2.4\\ &x = 2.4 + 1.2 \\ &x = 3.6 \end{aligned}\)