Question 5: Find x in the following case: 3+(10.x)=111
\(\begin{array}{l} 3 + \left( {10.x} \right) = 111 \Leftrightarrow 10.x = 111 – 3 \Leftrightarrow 10.x = 108\\ \Leftrightarrow x = 108:10 \Leftrightarrow x = 10.8 \end{array}\)
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Question 5: Find x in the following case: 3+(10.x)=111
\(\begin{array}{l} 3 + \left( {10.x} \right) = 111 \Leftrightarrow 10.x = 111 – 3 \Leftrightarrow 10.x = 108\\ \Leftrightarrow x = 108:10 \Leftrightarrow x = 10.8 \end{array}\)
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