Question 6: Find x in the following case: 3.(10+x)=111
\(\begin{array}{l} 3.\left( {10 + x} \right) = 111 \Leftrightarrow 10 + x = 111:3 \Leftrightarrow 10 + x = 37\\ \Leftrightarrow x = 37 – 10 \Leftrightarrow x = 27 \end{array}\)
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